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October 25, 2014

October 25, 2014

Posted by **angela** on Friday, June 1, 2012 at 10:07pm.

Show step by step work.

- geometry -
**MathMate**, Friday, June 1, 2012 at 11:08pmThe <-> operator is true only if both operands have the same truth value, i.e. TT or FF.

Given p is false and q is true, then ~p is true and ~q is false, therefore ~p <-> ~q is false.

Since the conditional p->q is false only if p is true and q is false, here we have

F->~r or

F->T

so it is true. Thus with p=F, q=T and r=F, the whole statement together is true,

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