Posted by Hannah on Friday, June 1, 2012 at 2:36pm.
A student, starting from rest, slides down a water slide. On the way down, a kinetic frictional force (a nonconservative force) acts on her. The student has a mass of 71 kg, and the height of the water slide is 12.0 m. If the kinetic frictional force does 7.4 × 103 J of work, how fast is the student going at the bottom of the slide? Use g = 9.81 m/s2
Could I use the equation
vf=sqrt v0^2 + 2(g)(h0hf) ?

Physics(Please respond)  bobpursley, Friday, June 1, 2012 at 3:23pm
No, not that equation.
final KE=initial PE  frictional loss
1/2 m vf^2=m*g*(12)7.4E3
solve for vf

Physics(Please respond)  Hannah, Friday, June 1, 2012 at 5:05pm
so for m

Physics(Please respond)  Hannah, Friday, June 1, 2012 at 5:06pm
So for m I would plug in 71kg correct?
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