Posted by HELP!!! DESPERATE D; on .
What is the smallest value of x at which f(x) intersects its non-vertical asymptote?
First we calculate the non-vertical (slant) asymptote as the leading term in the quotient represented by f(x), that is:
=9x/7 + .....
So g(x)=9x/7 is the non-vertical asymptote.
To solve f(x)=g(x), we can set
h(x)=f(x)-g(x)=0 and solve for x.
we need to take the common denominator of 49*x^2+63*x-49 and add the two terms together to get:
h(x) will vanish if and only if the numerator vanishes, which is the condition:
You only need to solve the quadratic equation n(x)=0 and select the smaller root.
Note: you need to check that the denominator of h(x) does not vanish at the same point!