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March 29, 2017

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If f(2) = 2.5 and f'(2) = -2.5, then f(2.5) is approximately...
I have no idea how to do this without an equation.

  • Calculus First Derivatives - ,

    Use linearization:
    f(2.5) = f(2)+(2.5-2.0)*f'(2) (approx.)
    =f(2)+0.5f'(2)
    I'll let you complete the answer.

  • Calculus First Derivatives - ,

    f(2) + 0.5f'(2) = 2.5 + (0.5)(-2.5) = 2.5 - 1.25 = 1.25, right? Thank you so much!

  • Calculus First Derivatives - ,

    Correct.
    The general formula for linearization is
    f(x+h)=f(x)+hf'(x) (approximately)
    In general, the smaller the value of h, the more accurate the answer would be.

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