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July 4, 2015

July 4, 2015

Posted by **hockeyfreak2011** on Thursday, May 31, 2012 at 2:53pm.

- 9th Grade Algebra -
**Damon**, Thursday, May 31, 2012 at 3:12pm4 x^2 - 16 x - 1 = 0

x = [ 16 +/- sqrt (256 + 16) ] / 8

x = [ 16 +/ - sqrt (16*17) ] / 8

x = 2 +/ - .5 sqrt 17

by the way by inspection you can see that it is going to be very close to

4 x^2 - 16 x = 0

x(x-4) = 0

x = 4 or 0