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Calculate the force on an electron (qe = -1.6 x 10^-19 C) in each of the following situations:

a.) moving at 2.0% the speed of light and perpendicular to a 3.0 T magnetic field

b.) 3.0 x 10^-6 m from a proton

c.) in Earth's gravitational field at the surface of Earth

  • Physics -

    (a) Lorentz force F =q•v•B•sinα.
    α= 90º, q=e,
    F =1.6•10^-19 •0.02•3•10^8•3 =
    (b) F=k•q1•q2/r² =
    9•10^9•(1.6•10^-19)²/3•10^-6 =
    (c) F =G• m•M/R².
    m(electron) = m = 9.1•10^-31 kg
    the gravitational constant G =6.67•10^-11 N•m²/kg²,
    Earth’s mass is M = 5.97•10^24 kg,
    Earth’s radius is R = 6.378•10^6 m.

  • Physics -

    Awesome, thanks Elena!

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