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January 31, 2015

Posted by **Christine** on Thursday, May 31, 2012 at 1:38am.

- College Physics -
**M BIL**, Thursday, May 31, 2012 at 2:35amSTEP 1:

Determine horizontal(x) and vertical (y) components of the initial velocity of golf ball.

Vy=Vsin55 = 50x.8191= 40.9 m/s, Vx=Vcos55 = 50x.5735= 28.6 m/s

STEP 2:

At maximum height, Vy=0.

Determine time (t) it takes to reach max. height.

Vy(final)=Vy(initial)+(-g)x(t)

Solve for (t):

0=40.9 x (-9.8) x t

0=40.9 x (-9.8 t)

9.8t=40.9, t=40.9/9.8, t= 4.17 sec

Since this half the total time in air, multiply by 2,

= 8.3 SEC (TOTAL T IN AIR)

STEP 3:

DETERMINE HIGHEST POINT REACHED BY BALL

h=((V**2)(Sin**2 55))/ 2g

h=((50**2) (.8191**2)) / 2 (9.8)

h=((2500)(.6710))/19.6

h= 85m Height reached

STEP 4:

DETERMINE 'RANGE' (total horizontal distance traveled)

R=Vx (t)

R=28.6 x 8.3

R=237.38 meters

- College Physics -
**Christine**, Thursday, May 31, 2012 at 3:26amthank you very much for your help M Bil

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