Determine horizontal(x) and vertical (y) components of the initial velocity of golf ball.
Vy=Vsin55 = 50x.8191= 40.9 m/s, Vx=Vcos55 = 50x.5735= 28.6 m/s
At maximum height, Vy=0.
Determine time (t) it takes to reach max. height.
Solve for (t):
0=40.9 x (-9.8) x t
0=40.9 x (-9.8 t)
9.8t=40.9, t=40.9/9.8, t= 4.17 sec
Since this half the total time in air, multiply by 2,
= 8.3 SEC (TOTAL T IN AIR)
DETERMINE HIGHEST POINT REACHED BY BALL
h=((V**2)(Sin**2 55))/ 2g
h=((50**2) (.8191**2)) / 2 (9.8)
h= 85m Height reached
DETERMINE 'RANGE' (total horizontal distance traveled)
R=28.6 x 8.3
thank you very much for your help M Bil
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