Monday

March 2, 2015

March 2, 2015

Posted by **Kelsey** on Thursday, May 31, 2012 at 12:42am.

17(sqrt10)/ 10

0

-17(sqrt10)/ 10

13(sqrt10)/ 10 ~

17. Find the distance between the lines with equations 5x + 12y = 12 and y = –x + 3. (1 point)

24/13 ~

48/13

-48/13

48/17

18. Find an equation of the line that bisects the acute angles formed by the lines with equations 2x + y – 5 = 0 and 3x – 2y + 6 = 0. (1 point)

(2SQRT13-3SQRT5)x+(SQRT13+2SQRT5)y-5SQ…

(-2SQRT13-3SQRT5)x+(-SQRT13+2SQRT5)y+5… ~

(-2SQRT13+3SQRT5)x+(-SQRT13-2SQRT5)y+5…

(-2SQRT13-3SQRT5)x+(-SQRT13+2SQRT5)y+5…

19. Find an equation of the line that bisects the acute angles formed by the lines with equations 4x + y + 3 = 0 and x + y – 2 = 0. (1 point)

(4SQRT2+SQRT17)x + (SQRT2+SQRT17)y + 3SQRT2 - 2SQRT17 = 0

(SQRT2+SQRT17)x - (4SQRT2+SQRT17)y + 3SQRT2 + 2SQRT17 = 0

(4SQRT2-SQRT17)x + (SQRT2+SQRT17)y + 3SQRT2 + 2SQRT17 = 0 ~

(SQRT2-SQRT17)x - (4SQRT2+SQRT17)y - 3SQRT2 - 2SQRT17 = 0

20. If 90° < < 180°, express cos in terms of tan . (1 point)

-SQRT(1/ 1 + tan^2 theta) ~

SQRT(1/ 1 + tan^2 theta)

SQRT(1 + tan^2 theta)

-SQRT(1 + tan^2 theta)

the one with ~ are my answers

- Precalculus check answers help! -
**Hannah**, Thursday, January 22, 2015 at 11:19amWere these right???????

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