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April 20, 2014

Homework Help: Precalculus check answers help!

Posted by Kelsey on Thursday, May 31, 2012 at 12:42am.

16. Find the distance between P (–2, 5) and the line with equation x – 3y + 4 = 0. (1 point)
17(sqrt10)/ 10
0
-17(sqrt10)/ 10
13(sqrt10)/ 10 ~

17. Find the distance between the lines with equations 5x + 12y = 12 and y = –x + 3. (1 point)
24/13 ~
48/13
-48/13
48/17



18. Find an equation of the line that bisects the acute angles formed by the lines with equations 2x + y – 5 = 0 and 3x – 2y + 6 = 0. (1 point)
(2SQRT13-3SQRT5)x+(SQRT13+2SQRT5)y-5SQ…
(-2SQRT13-3SQRT5)x+(-SQRT13+2SQRT5)y+5… ~
(-2SQRT13+3SQRT5)x+(-SQRT13-2SQRT5)y+5…
(-2SQRT13-3SQRT5)x+(-SQRT13+2SQRT5)y+5…

19. Find an equation of the line that bisects the acute angles formed by the lines with equations 4x + y + 3 = 0 and x + y – 2 = 0. (1 point)
(4SQRT2+SQRT17)x + (SQRT2+SQRT17)y + 3SQRT2 - 2SQRT17 = 0
(SQRT2+SQRT17)x - (4SQRT2+SQRT17)y + 3SQRT2 + 2SQRT17 = 0
(4SQRT2-SQRT17)x + (SQRT2+SQRT17)y + 3SQRT2 + 2SQRT17 = 0 ~
(SQRT2-SQRT17)x - (4SQRT2+SQRT17)y - 3SQRT2 - 2SQRT17 = 0

20. If 90° < < 180°, express cos in terms of tan . (1 point)
-SQRT(1/ 1 + tan^2 theta) ~
SQRT(1/ 1 + tan^2 theta)
SQRT(1 + tan^2 theta)
-SQRT(1 + tan^2 theta)

the one with ~ are my answers

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