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April 19, 2014

April 19, 2014

Posted by **Miranda** on Thursday, May 31, 2012 at 12:23am.

I have worked out the answer in my head, ($31) but is there a particular formula I can use or follow.

- Math -
**Kuai**, Thursday, May 31, 2012 at 1:43amLet's new = x, old = y

x+y = 45

x= y+17

y+17+y = 45

2y+17 = 45

2y+17-17=45- 17

2y = 28

2y/2 = 28/2

y = 14

x = y+17

x = 14+17

x = 31

So new tire cost $ 31 and used tire cost $ 14

- Math -
**Kuai**, Thursday, May 31, 2012 at 1:44amLet's new = x, old = y

x+y = 45

x= y+17

y+17+y = 45

2y+17 = 45

2y+17-17=45- 17

2y = 28

2y/2 = 28/2

y = 14

x = y+17

x = 14+17

x = 31

So new tire cost $ 31 and used tire cost $ 14

- Math -
**MathMate**, Thursday, May 31, 2012 at 4:08pmShort-cut for sum/difference problems:

Whenever the sum and difference of two numbers are both given, the bigger number is (sum+difference)/2, and the smaller number is (sum-difference)/2.

(45+17)/2=31

(45-17)/2=14

Most of the time these problems can be solved without pen and paper.

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