Posted by Kenz on Wednesday, May 30, 2012 at 10:13pm.
Find all solutions on the interval (0, 2pi) of the equation: 2(sin^2)t-3sint+1=0
how do you get this one started?
Math - MathMate, Wednesday, May 30, 2012 at 10:38pm
let s=sin(t), so
s=1/2 or s=1
sin(x)=1/2 or sin(x)=1
Now solve for x for 0≤x≤2π
Math - Kenz, Thursday, May 31, 2012 at 9:52pm
That makes so much sense. Thank you!
Math :) - MathMate, Friday, June 1, 2012 at 7:44am
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