Posted by **Kenz** on Wednesday, May 30, 2012 at 10:13pm.

Find all solutions on the interval (0, 2pi) of the equation: 2(sin^2)t-3sint+1=0

how do you get this one started?

- Math -
**MathMate**, Wednesday, May 30, 2012 at 10:38pm
let s=sin(t), so

2(sin^2)t-3sint+1=0

becomes

2s²-3s+1=0

(2s-1)(s-1)=0

=>

s=1/2 or s=1

=>

sin(x)=1/2 or sin(x)=1

Now solve for x for 0≤x≤2π

- Math -
**Kenz**, Thursday, May 31, 2012 at 9:52pm
That makes so much sense. Thank you!

- Math :) -
**MathMate**, Friday, June 1, 2012 at 7:44am
You're welcome!

## Answer This Question

## Related Questions

- math - Find all solutions to the equation tan(t)=1/tan (t) in the interval 0<...
- Math - Can I please get some help on these questions: 1. How many solutions does...
- Math - Directions: Find all solutions of the equation in the interval (0, 2pi) ...
- Pre-Calc - Find all solutions of the equation in the interval [0, 2pi). Show all...
- Math (Calc) - Find all solutions to the following equation on the interval 0<...
- Math - Find all solutions of the given equation in the interval [0, 2pi) cos x/2...
- math - find all solution to the equation 3 cos(x+4)=1. in the interval of 0<x...
- Trigonometry - Find all solutions of the equation in the interval [0,2pi] ...
- Pre-Calculus - cos^2(x) + sin(x) = 1 - Find all solutions in the interval [0, ...
- Trigonometry - Use the half-angle identities to find all solutions on the ...

More Related Questions