Posted by Noemi on .
describe how you would prepare 250.0 mL of a .500 M solution of NaCl by using apparatus found in a chemistry lab.
mols NaCl needed = M x L = 0.500 x 0.250 = about 0.125
grams NaCl = mols needed x molar mass = aboaut 0.125 x 58 (you need to use a better number than this estimate) = about 7.3 g.
Therefore, place 7.3 g NaCl in a 500 mL volumetric flask, add some water, swirl until all of the NaCl is dissolved, then add distilled water to the mark.