Post a New Question


posted by .

describe how you would prepare 250.0 mL of a .500 M solution of NaCl by using apparatus found in a chemistry lab.

  • Chemistry -

    mols NaCl needed = M x L = 0.500 x 0.250 = about 0.125
    grams NaCl = mols needed x molar mass = aboaut 0.125 x 58 (you need to use a better number than this estimate) = about 7.3 g.
    Therefore, place 7.3 g NaCl in a 500 mL volumetric flask, add some water, swirl until all of the NaCl is dissolved, then add distilled water to the mark.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question