Posted by **matt ** on Wednesday, May 30, 2012 at 6:52pm.

Two identical diverging lenses are separated by 15 cm. The focal length of each lens is -8.0 cm. An object is located 4.0 cm to the left of the lens that is on the left. Determine the final image distance relative to the lens on the right.

- physics -
**Elena**, Thursday, May 31, 2012 at 4:18am
For the first divergent lens

F1= - 8 cm,

object distance u = 4 cm.

Apply

1/F1 =1/v+1/u,

plug the value of F1 and u, and

solve for v

-1/8 = 1/4 + 1/v,

the image distance for first lens (to the left ofthe first lens)

v = -2.67cm.

Distance between two lences

d= 15 cm.

Image formed by the first lens is object to 2nd lens,

then object distance for 2nd lens is

u1 =15+v =17.67 cm (here take only magnitude,

because we have taken sign conventions)

Focal length of 2nd lens

F2 = - 8cm

apply

1/F2 =1/v1 +1/u1

plug values of F1 and u1 we get v1(that is image distance to the left of 2nd lens)

v1 =- 5.5 cm

-represants towards left of second lens.

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