five chips numbered 1 through 5 are placed in a bag. A chip is drawn and replaced. Then a second chip is drawn. Find the probability that the first chip is even and the other one is odd.
The probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
2/5 * 3/5 = ?
The probability of drawing an even chip is 2/5, and the probability of drawing an odd chip (which does not change due to replacement) is 3/5.
(2/5)*(3/5)
6/25
To find the probability that the first chip drawn is even and the second chip drawn is odd, we need to determine the total number of possible outcomes and the number of favorable outcomes.
First, let's determine the total number of possible outcomes. We have 5 chips numbered 1 through 5, so there are 5 possible outcomes for the first chip. Since the chip is replaced after it is drawn, there will still be 5 possible outcomes for the second chip. Therefore, the total number of possible outcomes is 5 * 5 = 25.
Next, let's determine the number of favorable outcomes, i.e., the outcomes where the first chip is even and the second chip is odd.
For the first chip to be even, we have 2 possibilities: 2 or 4.
For the second chip to be odd, we have 3 possibilities: 1, 3, or 5.
Hence, there are 2 * 3 = 6 favorable outcomes.
Finally, we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes:
Probability = (Number of favorable outcomes) / (Total number of possible outcomes) = 6 / 25 = 0.24.
Therefore, the probability that the first chip drawn is even and the second chip drawn is odd is 0.24 or 24%.