Posted by **Marco** on Wednesday, May 30, 2012 at 10:39am.

What is the radius of a communications satellite’s orbital path that is in a uniform circular orbit around Earth and has a period of exactly 24.0 hours (86,400 seconds). (Measurement is from the center of Earth.)

G = 6.67 × 10-11 N.m2/kg2

ME = 5.98 × 1024 kg

1 hr = 3,600 s

- physics -
**Elena**, Wednesday, May 30, 2012 at 1:40pm
The period is

T=2•π• sqrt (R³ /G•M)

Solve for R

- physics -
**Anonymous**, Thursday, May 9, 2013 at 3:28pm
What is the radius of a communications satellite’s orbital path that is in a uniform circular orbit around Earth and has a period of exactly 24.0 hours (86,400 seconds). (Measurement is from the center of Earth.)

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