Posted by dmkp on Wednesday, May 30, 2012 at 7:43am.
Let the x-axis point toward the center of curvature and the y-axis point upward. Use Newton’s second law.
ΣFy = N• cos θ − mg − f •sin θ = 0
ΣFx = N• sin θ + f •cos θ = m•v²/R,
Solving the 1st equation for N, we obtain
N =( f •sin θ + m•g)/cos θ,
Substitute N to the 2nd equation and obtain friction force
f =m[(v²•cosθ/R) - g•sinθ].
f=0 =>
(v²•cosθ/R) - g•sinθ = 0,
v²•cosθ/R = g•sinθ,
v² /R•g = sinθ/cosθ = tanθ.
v =sqrt(R•g•tanθ) = sqrt (50•9.8•tan16º)=11.85 m/s
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