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October 25, 2014

October 25, 2014

Posted by **PLZ HELP ME NOW...** on Wednesday, May 30, 2012 at 6:03am.

a)acceleration in first 10 sec.

b)acceleration in last 50 sec.

c)the total distance traveled by the train in whole journey

d)average velocity of the trip.

- physics -
**drwls**, Wednesday, May 30, 2012 at 6:35ama) (Velocity change)/Time = 2.0 m/s^2

b) (Velocity change)/Time = -0.4 m/s^2

c) X1 + X2 + X3, where X1 is the distance travelled accelerating; X2 is the distance travelled at constant speed and X3 is the distance travelled while decelerating.

= 10*10 + 20*200 + 10*50 = ___ m

Average speed was used for X1 and X3.

d) Divide previous answer by total elapsed time, 260 s.

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