Thursday

November 27, 2014

November 27, 2014

Posted by **PLZ HELP ME NOW...** on Wednesday, May 30, 2012 at 6:03am.

a)acceleration in first 10 sec.

b)acceleration in last 50 sec.

c)the total distance traveled by the train in whole journey

d)average velocity of the trip.

- physics -
**drwls**, Wednesday, May 30, 2012 at 6:35ama) (Velocity change)/Time = 2.0 m/s^2

b) (Velocity change)/Time = -0.4 m/s^2

c) X1 + X2 + X3, where X1 is the distance travelled accelerating; X2 is the distance travelled at constant speed and X3 is the distance travelled while decelerating.

= 10*10 + 20*200 + 10*50 = ___ m

Average speed was used for X1 and X3.

d) Divide previous answer by total elapsed time, 260 s.

**Answer this Question**

**Related Questions**

physics - a train starts from rest and accelerates uniformly to achieve a ...

physics - a train starts from rest and accelerates uniformly to achieve a ...

physics - a train starts from rest and accelerates uniformly at 100m/min^2 for ...

physics - a train starts from rest and accelerates uniformly at 100m/min^2 for ...

physics - a train starts from rest and accelerates uniformly at 100m/min^2 for ...

physics - a car traveled at uniform velocity of 20m/sec for 5 sec the brakes are...

physics - a body moves with a uniform velocity of 2m/sec for 5 sec then velocity...

physics - a cyclist start from rest and accelerate uniformly to achieve a ...

physics - A student starts from rest from his house and accelerates uniformly at...

math - The train slows down uniformly from a speed of 50m/s to a speed of 10m/s ...