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Posted by HELP PLEASE! on Wednesday, May 30, 2012 at 1:15am.

The diameter of a circle has endpoints P(–10, –2) and Q(4, 6). a.Find the center of the circle. b.Find the radius. If your answer is not an integer, express it in radical form. c.Write an equation for the circle.

The centre must be the midpoint of PQ which would be C( (-10+4)/2 , (-2+6)/2 ) = C(-3,2) radius is √( (4+3)^2 + (2-6)^2) = √65 equation: (x+3)^2 + (y-2)^2 = 65

Length of the diameter of a circle with the endpoints A(4, -3) and B(4, 3)

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