Precalculus check answers help!
posted by Kelsey .
1.) Find an expression equivalent to sec theta sin theta cot theta csc theta.
tan theta
csc theta
sec theta ~
sin theta
2.) Find an expression equivalent to cos theta/sin theta .
tan theta
cot theta ~
sec theta
csc theta
3.) Simplify (tan^2 theta + 1)/(tan^2 theta) .
csc2 theta
–1
tan2 theta
1 ~
4.) Use a sum or difference identity to find the exact value of sin 15°.
(sqrt)2  (sqrt)6/ 4
(sqrt)6  (sqrt)2/ 4 ~
(sqrt)6 + (sqrt)2/ 4
(sqrt)2  (sqrt)6/ 4
5.) Which expression is equivalent to cos (theta – 2pi)?
–cos theta
sin theta
cos theta ~
–sin theta
the ones with ~ are my answers!

1), 3) check your algebra
4) I'm not sure where you went wrong on this one. However, sqrt(6)sqrt(2)/4 is greater than 1 (2.0959 in fact)
2), 5) are correct 
is 3 1?
and im not sure what i did on number 1 ? please explain. 
1)
secØ sinØ cotØ cscØ
= (1/cosØ)(sinØ)(cosØ/sinØ)(1/sinØ)
= 1/sinØ
= cscØ 
find an expression equivalent: sec θ  sin θ tan θ=