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September 3, 2014

September 3, 2014

Posted by **Anonymous** on Tuesday, May 29, 2012 at 8:00pm.

dy/dx = x (y^(1/3))

- CALCULUS -
**bobpursley**, Tuesday, May 29, 2012 at 8:31pmx dx=dy/y^1/3

1/2 x^2=y^2/3 * 3/2

x^2=3y^2/3

then put it in any form you wish.

- CALCULUS -
**Anonymous**, Tuesday, May 29, 2012 at 8:45pmHow could I rearrange this to form y=? Out of all the combinations I have tried, I can't find any that satisfy the initial condition f(2)=8.

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