CALCULUS
posted by Anonymous .
Solve the differential equation:
dy/dx = x (y^(1/3))

x dx=dy/y^1/3
1/2 x^2=y^2/3 * 3/2
x^2=3y^2/3
then put it in any form you wish. 
How could I rearrange this to form y=? Out of all the combinations I have tried, I can't find any that satisfy the initial condition f(2)=8.