Posted by Anonymous on Tuesday, May 29, 2012 at 8:00pm.
Solve the differential equation:
dy/dx = x (y^(1/3))

CALCULUS  bobpursley, Tuesday, May 29, 2012 at 8:31pm
x dx=dy/y^1/3
1/2 x^2=y^2/3 * 3/2
x^2=3y^2/3
then put it in any form you wish.

CALCULUS  Anonymous, Tuesday, May 29, 2012 at 8:45pm
How could I rearrange this to form y=? Out of all the combinations I have tried, I can't find any that satisfy the initial condition f(2)=8.
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