Posted by Mark on Tuesday, May 29, 2012 at 7:41pm.
Imagine two triangles:
1) ΔABC : point A (where the cord is attached ), point B (where the aerialist holds the trapeze at initial position), point C (the intersection of the vertical line from A and horizontal line from B),
2) ΔADM: point M (where the aerialist holds the trapeze at its left position), point D (the intersection of the vertical line from A and horizontal line from M)
AC = AB•cosθₒ =L•cosθₒ,
AD =AM•cosθ = L•cosθ,
CD = d.
AD =AC +CD,
L•cosθ = L•cosθₒ +d.
cosθ =( L•cosθₒ +d)/L =
=(8•cos41º+0.75)/8 = 0.848.
arcos 0.848 = 32º.
arccos 0.848 = 32º.
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