Posted by Anonymous on Tuesday, May 29, 2012 at 7:40pm.
If dy/dx = x (cos x^2) and y = −3 when x = 0, when x = pi, y = .
A. −3.215
B. sqrt(2)
C. 1.647
D. 6
E. 3pi
For some odd reason, I keep getting 0.5325989. I can't come up with any of the answers given.

CALCULUS (REPOST)  MathMate, Tuesday, May 29, 2012 at 8:59pm
I=∫ xcos(x²)dx
sub u=x², du=2xdx
I=∫cos(u)du/2
=sin(u)/2+C
When x=0, u=0, y=3 => C=3
so
y=sin(x²)/23
So calculate
y=sin(π²)3
Note that if you use your calculator, make sure you put the angle to be in radians mode to get the correct answer.

CALCULUS (REPOST)  Anonymous, Wednesday, May 30, 2012 at 8:51am
y=sin(pi^2)3 yields approximately 3.430301217, which still doesn't fit the bill for the options I am given.

CALCULUS (REPOST)  MathMate, Wednesday, May 30, 2012 at 2:29pm
Sorry that there was a typo (I forgot to divide sin(x²) by 2):
y=sin(x²)/23
So calculate
y=sin(π²)/23
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