Posted by **Anonymous** on Tuesday, May 29, 2012 at 7:40pm.

If dy/dx = x (cos x^2) and y = −3 when x = 0, when x = pi, y = .

A. −3.215

B. sqrt(2)

C. 1.647

D. 6

E. 3pi

For some odd reason, I keep getting -0.5325989. I can't come up with any of the answers given.

- CALCULUS (REPOST) -
**MathMate**, Tuesday, May 29, 2012 at 8:59pm
I=∫ xcos(x²)dx

sub u=x², du=2xdx

I=∫cos(u)du/2

=sin(u)/2+C

When x=0, u=0, y=-3 => C=3

so

y=sin(x²)/2-3

So calculate

y=sin(π²)-3

Note that if you use your calculator, make sure you put the angle to be in radians mode to get the correct answer.

- CALCULUS (REPOST) -
**Anonymous**, Wednesday, May 30, 2012 at 8:51am
y=sin(pi^2)-3 yields approximately -3.430301217, which still doesn't fit the bill for the options I am given.

- CALCULUS (REPOST) -
**MathMate**, Wednesday, May 30, 2012 at 2:29pm
Sorry that there was a typo (I forgot to divide sin(x²) by 2):

y=sin(x²)/2-3

So calculate

y=sin(π²)**/2**-3

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