Mathematics Word Problems Coin problems
Stu has $21.40 in dimes and quarters for a totl of 100 coins. How many of each kind of coin does he have?
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D = 2N, Q = D+10 N + D + Q = 210 N + 2N + (2N + 10) = 210 Solve for N, then D and Q.
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q(.25) + (100-q)(.1) = 15.70 .25 q + 10 - .1 q = 15.7 .15 q = 5.7 q = 38 then dimes = 100 - 38 = 62
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SOLVING SYSTEMS: A bag contains nickels, dimes and quarters having a value of $3.75. If there are 40 coins in all and 3 times as
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Clearly the answers you listed do not work, since 15 ≠ 3*10 When you worked it out, did you check
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SOLVING SYSTEMS: A bag contains nickels, dimes and quarters having a value of $3.75. If there are 40 coins in all and 3 times as
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n+d+q = 40 d = 3q 5n+10d+25q = 375 Now let 'er rip
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