Posted by **Anonymous** on Tuesday, May 29, 2012 at 4:18pm.

AB = 8 cm, AC = 6 cm, AD = 7 cm, CD = 2.82 and CAB=50°. Find the length BC, angle ABC, angle CAD , area of triangle ACD

- math -
**Reiny**, Tuesday, May 29, 2012 at 4:57pm
Start off with the cosine law to find BC

BC^2= 8^2 + 6^2 - 2(8)(6)cos50°

..

..

BC = 6.188

Now use the sine law to find angle B

For angle CAD, use the cosine law again

7^2 = 6^2 + 2.82^2 - 2(6)(2.82)cos C

cos C = -.14916..

angle C = 98.578°

to find the area of a triangle use

area = (1/2)ab sin Ø , where Ø is the contained angle between sides a and b

I would use angle C as that contained angle and sides 6 and 2.82

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