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August 29, 2014

August 29, 2014

Posted by **Abby** on Tuesday, May 29, 2012 at 3:37pm.

- ap calculus -
**Count Iblis**, Tuesday, May 29, 2012 at 3:43pmStart by finding the zeroes of the denominator.

- ap calculus -
**Steve**, Tuesday, May 29, 2012 at 3:45pmsince x^2+5x+6 = (x+2)(x+3)

and x^2-4 = (x+2)(x-2)

f(x) = (x+3)/(x-2) for x ≠ -2

so, x = -2 is a removable discontinuity,

x = 2 is a nonremovable discontinuity

extra credit: how do we remove the discontinuity at x = -2?

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