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April 18, 2014

April 18, 2014

Posted by **ridhi** on Tuesday, May 29, 2012 at 1:03am.

please explain me the steps.

thanks in advance :)

- physics(heat) -
**Elena**, Tuesday, May 29, 2012 at 4:46pmLet the final temperature of the mixture = 100ºC.

Heat gained by ice and iced water Q1 is

Q1 = m•λ + m•c•ΔT = 200•80 + 200•1•100 = 3600 cal.

Q2 = (m1•c +W) •(100º -0º) =(250•1 + 50) •100 = 30000 cal.

Q =Q1+Q2 = 36000 +30000 = 66000 cal.

If entire steam condensed the total heat given by it is

Q3 = m•L = 200•540= 108000 cal.

Now the total heat available is 108000 cal, but only 66000 cal are required. Therefore? all the steam will not get condensed.

Final temperature of the mixture is 100ºC.

Mass of steam condensed is 66000/540=122.2 g.

Mass of the contents is 250 +200 + 122.2 = 572.2 g

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