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November 27, 2014

November 27, 2014

Posted by **Laura** on Monday, May 28, 2012 at 11:34pm.

- Calculus AB...I really need help -
**Steve**, Tuesday, May 29, 2012 at 4:01amv = ∫πy^2 dx [0,π]

= ∫πcos^2(cosx) dx [0,π]

that is not something you can evaluate using elementary functions. wolframalpha can do it, but it's done numerically, fer shure!

- Calculus AB...I really need help -
**Count Iblis**, Tuesday, May 29, 2012 at 3:40pmUsing cos(2 x) = 2 cos^2(x) - 1 and the definition of the Bessel function of zeroth order:

J0(x) = 1/pi Integral from zero to pi of cos[x cos(t)] dt,

you find that the volume is given by:

pi^2/2 [1 + J0(2)]

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