how did you come to this answer?
The answer is approximately =0.017
b) Ten Cobalts are randomly selected and the miles per gallon for each car are recorded. What is the probability that the mean miles per gallon exceed 34 miles per gallon?
The final answer will be = 0.0351
To calculate the probability that the mean miles per gallon of the randomly selected Cobalts exceeds 34 miles per gallon, you would need some additional information.
Assuming you have a sample that follows a normal distribution, you can use the Central Limit Theorem to approximate the distribution of the sample mean. The Central Limit Theorem states that as the sample size increases, the distribution of the sample mean approaches a normal distribution, regardless of the shape of the population distribution.
In this case, you need to know the mean and standard deviation of the population miles per gallon for Cobalts. Let's assume the population mean is μ and the population standard deviation is σ.
The probability that the mean miles per gallon exceeds 34 miles per gallon can be calculated using the Z-score formula:
Z = (X - μ) / (σ / √n)
Where:
X is the desired mean value (34 miles per gallon in this case)
μ is the population mean
σ is the population standard deviation
n is the sample size (in this case, 10)
Once you have the Z-score, you can use a Z-table or a statistical calculator to find the probability associated with that Z-score.
Now, if you already have the mean and standard deviation for the population, you can calculate the Z-score and find the probability that way. However, without those data points, it is not possible to determine how exactly the answer of 0.0351 was obtained.