Posted by **parul** on Monday, May 28, 2012 at 3:06am.

a train starts from rest and accelerates uniformly at 100m/min^2 for 10 min.then it maintains a constant velocity for remaining 20 min.brakes are applied and train uniformly retards and comes to rest in next 5 min.

a)the maximum velocity reached

b)the retardation in last 5 min

c)total distance traveled

d)the average velocity of the train.

- physics -
**Henry**, Wednesday, May 30, 2012 at 9:34pm
a. V = Vo + at

V = 0 + 100m/min^2 * 10min = 1000 m/min

b. a=(V-Vo)/t=(0-1000) / 5=-200m/min^2

c. d1 = 0.5a*t^2 = 50*10^2 = 5000 m.

d2 = 1000m/min * 20min = 20,000 m.

d3 = Vo*t + 0.5a*t^2

d3 = 1000*5 + (-100)*5^2 = 2500 m.

d1+d2+d3 = 5000 + 20000 + 2500=27,500 m

= Tot. dist. traveled.

d. T = t1 + t2 + t3 = 10+20+5 = 35 Min.

Va=(d1+d2+d3)/T=27,500m/35min=786 m/min

= Average velocity.

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