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November 23, 2014

November 23, 2014

Posted by **Anonymous** on Sunday, May 27, 2012 at 8:59pm.

- math -
**Reiny**, Sunday, May 27, 2012 at 9:42pmby Pythagoras, I found AC = 40 (that's the easy part)

So the area of triangle ABC = (1/2)(75)(40) = 1500

In triangle ACD , we need an angle, let's find angle D

40^2 = 50^2 + 60^2 - 2(50)(60)cosD

6000cosD = 2500+3600-1600

cosD = 4500/6000 = .75

angle D = 41.41°

area of triangle ACD = (1/2)(50)(60)sin41.41° = 992.156..

total area = 992.16 + 1500 = 2492.16

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