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December 20, 2014

December 20, 2014

Posted by **Randy** on Sunday, May 27, 2012 at 7:14pm.

19dc/d^2-c^2 - d-c/d+c

- algebra -
**Reiny**, Sunday, May 27, 2012 at 7:39pmYou must mean ....

19cd/(d^2 - c^2) - (d-c)/(d+c)

then ...

= 19cd/((d+c)(d-c) - (d-c)/(d+c)

LCD is (d+c)(d-c)

= ( 19cd - (d-c)(d+c) )/((d+c)(d-c) )

= (c^2 + 19cd - d^2)/(d^2 - c^2)

not much of a simplication.

Confirm if my assumption of the question was correct.

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