Posted by Liz on Sunday, May 27, 2012 at 4:22pm.
The curves intersect at (0,0) and (1,1).
Using shells,
v = ∫2πrh dx [0,1]
where r = x and h=√x-x^2
v = 2π∫x(√x-x^2) dx [0,1]
= 3π/10
Using discs,
v = ∫π(R^2-r^2) dy [0,1]
where R=√y and r=y^2
v = π∫(y-y^4) dy [0,1]
= 3π/10
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