Homework Help: physics

Posted by srikala on Sunday, May 27, 2012 at 1:50pm.

the equation of a transverse wave travel ling on a rope is given by y=10sin3.14(0.01x-2.00t)where y and x are in cm and t is in seconds.the maximum transverse speed of the particle in the rope is about
options:
1. 62.8 cm/s
2. 75 cm/s

physics - Damon, Sunday, May 27, 2012 at 4:09pm
dy/dt = -10*2*3.14 cos****
max of cos is 1
so 20*3.14 = 62.8
physics - Elena, Sunday, May 27, 2012 at 4:24pm
y=10sin 3.14(0.01x-2.00t)=
= 10sin (π•x/100 - 2•π•t).
General form is
y= Asin (2π•x/λ - ω•t).
v =dy/dt =- A •ω cos (2•π•x/λ - ω•t).
v(max) = A •ω,where A =10 cm, ω = 2•π (rad/s),
v(max) = 20• π =62.8 cm/s

Answer this Question

Related Questions

Physics - For a certain transverse wave, the distance between two successive ...
physics - the equation of transverse wave on a rope is y(x,t)=5sin(4.0t-0.02x) ...
physics - The equation of transverse wave on a rope is y (x, t) = 5 sin (4.0t &...
Physics - Earthquakes are essentially sound waves travelling through the earth. ...
Physics - For a certain transverse wave, the distance between two successive ...
Physics - For a certain transverse wave, the distance between two successive ...
Physics - For a certain transverse wave, the distance between two successive ...
physics waves transverse longitudinal - i real stuck on this and i really want ...
Physics - The distance between two successive crests of a certain transverse ...
Physics - The distance between two successive crests of a certain transverse ...

For Further Reading

First Name:
School Subject:
Answer: