Posted by srikala on Sunday, May 27, 2012 at 1:50pm.
the equation of a transverse wave travel ling on a rope is given by y=10sin3.14(0.01x2.00t)where y and x are in cm and t is in seconds.the maximum transverse speed of the particle in the rope is about
options:
1. 62.8 cm/s
2. 75 cm/s

physics  Damon, Sunday, May 27, 2012 at 4:09pm
dy/dt = 10*2*3.14 cos****
max of cos is 1
so 20*3.14 = 62.8

physics  Elena, Sunday, May 27, 2012 at 4:24pm
y=10sin 3.14(0.01x2.00t)=
= 10sin (π•x/100  2•π•t).
General form is
y= Asin (2π•x/λ  ω•t).
v =dy/dt = A •ω cos (2•π•x/λ  ω•t).
v(max) = A •ω,where A =10 cm, ω = 2•π (rad/s),
v(max) = 20• π =62.8 cm/s
Answer This Question
Related Questions
 physics  the equation of transverse wave on a rope is y(x,t)=5sin(4.0t0.02x) ...
 physics  The equation of transverse wave on a rope is y (x, t) = 5 sin (4.0t &#...
 Physics  A uniform rope with length L and mass m is held at one end and whirled...
 Physics  A wave can be propagated on a rope by holding one end of the rope and ...
 Physics  The equation of a transverse wave traveling along a very long string ...
 physics  A sinusoidal transverse wave of amplitude ym = 6.4 cm and wavelength...
 physics  A sinusoidal transverse wave of amplitude ym = 3.2 cm and wavelength...
 Physics  A wave on a string is described by: y=(3.6cm)sin(2.7x−3.1t +0.97...
 AP Physic  Hi there I am having a lot of trouble trying to figure out this ...
 Physics(wave motion and propagation)  A uniform heavy rope hangs freely from a ...
More Related Questions