Posted by **parul** on Sunday, May 27, 2012 at 10:23am.

A cyclist is cycling at uniform velocity of 8m/sec for 8 sec then applies brakes and cycle come to rest in next 10 sec. calculate

a)Distance traveled by uniform velocity.

b)distance traveled by non-uniform velocity

c)total distance traveled

d)the average velocity in entire journey

- physics -
**Elena**, Sunday, May 27, 2012 at 3:54pm
(a) s1 =v•t =8•8 =64 m,

(b)

v(final) =v - a•t,

v(final) =0,

a =v/t,

s =v•t - at²/2 =

= v•t - v•t²/2•t =v•t/2=8•8/2=32 m.

(c)

s =s1+s2 = 64+32 = 96 m.

(d)

v(ave) = s/t =96/(8+10) = 5.33 m/s.

- physics -
**avinav kumar chourasia**, Tuesday, April 14, 2015 at 1:27am
a)uniform velocity=8m/s t1=8sec t2=10

d=s*t =8*8=64m

b) v=u+at

due to retardation v=u-at

0=u-at

u=at

a=u/t

s=ut+1/2*at^2

s=ut/2

s=64/2=32

c)total disct.=96m

d)avg velocity=total displacement/total time

=96/18=48/9

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