Posted by parul on Sunday, May 27, 2012 at 10:23am.
A cyclist is cycling at uniform velocity of 8m/sec for 8 sec then applies brakes and cycle come to rest in next 10 sec. calculate
a)Distance traveled by uniform velocity.
b)distance traveled by nonuniform velocity
c)total distance traveled
d)the average velocity in entire journey

physics  Elena, Sunday, May 27, 2012 at 3:54pm
(a) s1 =v•t =8•8 =64 m,
(b)
v(final) =v  a•t,
v(final) =0,
a =v/t,
s =v•t  at²/2 =
= v•t  v•t²/2•t =v•t/2=8•8/2=32 m.
(c)
s =s1+s2 = 64+32 = 96 m.
(d)
v(ave) = s/t =96/(8+10) = 5.33 m/s.

physics  avinav kumar chourasia, Tuesday, April 14, 2015 at 1:27am
a)uniform velocity=8m/s t1=8sec t2=10
d=s*t =8*8=64m
b) v=u+at
due to retardation v=uat
0=uat
u=at
a=u/t
s=ut+1/2*at^2
s=ut/2
s=64/2=32
c)total disct.=96m
d)avg velocity=total displacement/total time
=96/18=48/9
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