posted by parul on .
A cyclist is cycling at uniform velocity of 8m/sec for 8 sec then applies brakes and cycle come to rest in next 10 sec. calculate
a)Distance traveled by uniform velocity.
b)distance traveled by non-uniform velocity
c)total distance traveled
d)the average velocity in entire journey
(a) s1 =v•t =8•8 =64 m,
v(final) =v - a•t,
s =v•t - at²/2 =
= v•t - v•t²/2•t =v•t/2=8•8/2=32 m.
s =s1+s2 = 64+32 = 96 m.
v(ave) = s/t =96/(8+10) = 5.33 m/s.
a)uniform velocity=8m/s t1=8sec t2=10
due to retardation v=u-at
d)avg velocity=total displacement/total time