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physics

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A student starts from rest from his house and accelerates uniformly at the rate of 2m/sec^2 for 30 sec then he apply break for 45 sec and come to rest at his school.how far is his school

  • physics -

    d = 0.5a*t^2
    d1 = 1*30^2 = 900 m. = Distance traveled in 30 s.
    V = at = 2*30 = 60 m/s = Velocity reached in 30 s.

    a=(V-Vo)/t = (0-60) / 45 = -1.33 m/s^2.
    V^2 = Vo^2 + 2a*d
    0 = 60^2 - 2.66d
    2.666d = 3600
    d2 = 1350 m.

    d1 + d2 = 900 + 1350 = 2250 m. =
    Distance from house to school.

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