Posted by Anonymous on Saturday, May 26, 2012 at 3:04pm.
Andrea, Betty, Joyce, Karen, and Paula are starters on their school basketball team. How many different groups of three can be chosen for a newspaper photo?

Algebra 1  Reiny, Saturday, May 26, 2012 at 3:05pm
You are looking for C(5,3)
which is 10

Algebra 1  Anonymous, Saturday, May 26, 2012 at 3:09pm
5! / 3!(53)! = 120 / 6(2) = 120/12 = 10
There are 10 different groups of three possible for the given combinations problem.
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