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December 20, 2014

December 20, 2014

Posted by **Anonymous** on Saturday, May 26, 2012 at 3:04pm.

- Algebra 1 -
**Reiny**, Saturday, May 26, 2012 at 3:05pmYou are looking for C(5,3)

which is 10

- Algebra 1 -
**Anonymous**, Saturday, May 26, 2012 at 3:09pm5! / 3!(5-3)! = 120 / 6(2) = 120/12 = 10

There are 10 different groups of three possible for the given combinations problem.

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