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August 2, 2014

August 2, 2014

Posted by **srikala** on Saturday, May 26, 2012 at 5:43am.

options

1. 5s,150 cm

2. 10s,150 cm

- physics -
**ajayb**, Saturday, May 26, 2012 at 9:01amAssume the particle's acceleration is a cm/sec^2 and that it moves a distance of S(t)cms in total time of t secs. Also it covers S(t-1) cms. in (t-1) secs.

Since it covers 6cm in the first second => 6 = 0.1 + (1/2).a.1^2 => a=12cm/sec^2.

Now, S(t)-S(t-1)= (1/2).a.[t^2-(t-1)^2]......(1)

Also, S(t)-S(t-1)= (9/25).S(t)= (9/25).(1/2).a.t^2 .....(2)

From the above two equations, you will get the following eqn.

9t^2-50t+25 = 0

Solve it to get two values for t i.e. t=5,10/18 (ignore the second as t is not less than 1sec)

Thus t=5sec and hence S(t)=150cm

Therefore,option (1) is correct.

=

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