Posted by Bo on Friday, May 25, 2012 at 3:17pm.
Take a piece of paper and note the following on your diagram. It will be difficult to follow without an annotated diagram.
Label the (horizontal) diameter as CD, with C on the left.
Label the chord 16 units long as PA (P on the left).
Label the chord 12 units long as QB (Q on the left).
Label the centre of the circle as O.
Construct a (vertical) diameter perpendicular to CD. Label the ends as E (on top) and F (at the bottom).
Label the intersection PA and EF as X, and the distance OX=x.
Label the intersection QB and EF as Y, and the distance OY=y.
Label the radius of the circle as r = OD.
Confirm that:
OD=OE=OC=OF=r=10
PX=XA=8
QY=YB=6
We don't know yet the distances x and y.
By the theorem of intersection of chords, we have
PX*XA = FX*XE
8²=(10-x)(10+x)
Solve for x to get 6.
θ1=∠AOD=sin-1(6/10)
Similarly,
QY*YB=(10-y)(10+y)
6²=(10-y)(10+y)
Solve for y to get 8.
θ2=∠BOD=sin-1(6/10)
⇒
φ=∠BOA=θ2-θ1
Arc length of AB
=rφ/2π
=10φ/2π
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