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July 30, 2014

July 30, 2014

Posted by **Rachel** on Friday, May 25, 2012 at 2:56pm.

P coordinates: (1.25, 0)

R coordinates: (0, 1.25)

Q is directly between the two

- Physics -
**Elena**, Friday, May 25, 2012 at 3:18pmfrequency f = 2 rev/s

angular velocity = 2•π•f = 4•π rad/s

(a) Velocity vector at P = (1.25x4x3.14)j = 15.7 j,

where j is unit vector along positive y axis.

Also velocity vector of the particle at R = -15.7i,

where i is unit vector along positive x direction.

As the direction changes uniformly,

the average velocity over the interval PR is

(15.7/2)(j-i)= 7.85(j-i).

Magnitude = sqrt[7.85^2+7.85^2] =

=1.414x7.85 = 11.10 m/s

and the direction is 45 degrees west of north.

(b) Average velocity, V1 over interval PQ is

= 0.5{15.7 j + [15.7/sqrt(2)](j-i)} or

V1 = 0.5[26.80 j - 11.10i] = 13.40 j - 5.55 i.

Magnitude of V1 = sqrt[13.40^2 + 5.55^2] = 14.50 m/s.

due theta west of north given by theta = tan^-1 [5.55/13.40] = 22.5 degrees west of north.

(c) v= 2•π•f•R = 15.7 m/s due north

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