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March 27, 2017

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1) A force vector has a magnitude of 579 newtons and points at an angle 43o of below the positive x axis.

Find the x scalar component and the y scalar component of the vector?

For the x component I did 579cos(43) = 423.45 N. Is this correct?

For the y component I did 579sin(43) but this was incorrect. I am not sure what to do.

  • Physics(Please help) - ,

    The angle is -43°, not 43°

    The vector points below the x-axis, so sin is negative.

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