Posted by Megan on Friday, May 25, 2012 at 2:42pm.
by speed, do you mean the vector sum of the horizontal and vertical speeds?
Must be, since the horizontal speed never changes, and the initial vertical speed was 0, so double that is still 0.
v = 4.3i - 9.8tj
|v| = √(4.3^2 + (9.8t)^2) = √(96.04t^2 + 18.49)
so, double the original speed is 8.6m/s and we want to find t when
8.6 = √(96.04t^2 + 18.49)
t = 0.76 sec
This is the projectile thrown with horizontal velocity.
So
v(x) = const,
v(y) = g•t.
v ² = v(x)² +v(y)²
v =2•v(x),
[2v(v)]² = v(x)² +v(y)²,
3•v(x)² =v(y)² = (g•t)²,
t =v(x) •√3/g =4.3•1.73/9.8 =0.76 s.
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