Posted by j on Friday, May 25, 2012 at 12:12pm.
I assume the plane needs to pass through the mid-point between the two points, and perpendicular to the line joining the two points.
First find the mid-point by
M((x1+x2)/2,(y1+y2)/2,(z1+z2)/2)
The normal vector for the plane is just the vector AB, or N(3-(-1),1-2,-4-4)=(4,-1,-8).
The equation for the plane is then:
4(x-xm)-(y-ym)-8(z-zm)=0
where M(xm,ym,zm) as calculated above.
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