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March 31, 2015

March 31, 2015

Posted by **Michael** on Friday, May 25, 2012 at 10:25am.

Part (a)

Is the sample data consistent with the cahiers’ claim? Please answer “yes” or “no” and provide a brief explanation.

Part (b)

Using a significance level of 0.05, can we reject the cashiers’ claim? Please make sure to show your work!

Part (c)

Look at the answers to Parts (a) and (b). At first glance, they may seem contradictory. Explain how that seeming contradiction can be resolved in the context of hypothesis testing.

- Statistics -
**MathGuru**, Friday, May 25, 2012 at 6:28pmHere are a few hints:

Ho: p ≥ .80 -->null hypothesis

Ha: p < .80 -->alternate hypothesis

You can try a proportional one-sample z-test for this one since this problem is using proportions.

Using a formula for a proportional one-sample z-test with your data included, we have:

z = .76 - .80 -->test value (102/135 is approximately .76) minus population value (.80) divided by

√[(.80)(.20)/135] --> .20 represents 1-.80 and 135 is sample size.

Finish the calculation. Remember if the null is rejected, then p < .80 . If the null is not rejected, then p could very well be greater than or equal to .80 in the population of interest.

I hope this will help get you started.

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