Posted by DK on Friday, May 25, 2012 at 9:24am.
y = ln((e^(-2x))(cos4x))
= ln(e^-2x) + ln(cos 4x)
= -2x + ln(cos 4x)
y' = -2 - 4sin4x/cos4x
= -2 - 4tan4x
Related Questions
Pre-Calculus - Find all solutions to the equation in the interval [0, 2pi) cos4x...
trig - Prove that cos4x=8cos^4x-8cos^2x+1 so I'm guessing you begin with the...
calculus - y = (ln x)^(cos4x) Use logarithmic differentiation to find the ...
Math - Trig - Double Angles - Prove: cos4x = 8cos^4x - 8cos^2x + 1 My Attempt: ...
Calculus - First Derivative - Original Equation: f(x) = e^(-x) - e^(-2x) Did I ...
Calculus - I need to find the second derivative of y=x(x-1)^1/2. I found the ...
calc - derivative of (x^3/6)+(1/2x)? i got (x^2/2)-(1/2x^2) is that correct? and...
Math-trigonometry - Several questions from my homework, any are appreciated. ...
Maths Calculus Derivative Integral - Urgent Please - Use 2nd Fundamental Theorem...
Calculus - relative extrema x^4-2x^2+5 so far I know how to find the derivative ...
For Further Reading