Posted by **srikala** on Friday, May 25, 2012 at 2:47am.

if a car covers 2/5th of the total distance with v1 speed and 3/5th distance with v2 then average speed is?

- physics -
**Elena**, Friday, May 25, 2012 at 2:32pm
The time

for the first part is

t1 =2•s/5•v1,

for the second part is

t2 = 3•s/5•v2.

The total time is

t =t1+t2 =

=(2•s/5•v1)+( 3•s/5•v2)=

=(s/5) •(2/v1 + 3/v2) =

=(s/5) •{(2•v2+3•v1)/(v1•v2)},

v(ave) = distance/total time =

=s/[(s/5) •{(2•v2+3•v1)/(v1•v2)}]=

=5•(v1•v2)/(3•v1+2v2).

- physics -
**sree sai**, Friday, June 24, 2016 at 10:28am
5v1v2/3v1+2*3/5

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