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Posted by on Friday, May 25, 2012 at 2:47am.

if a car covers 2/5th of the total distance with v1 speed and 3/5th distance with v2 then average speed is?

  • physics - , Friday, May 25, 2012 at 2:32pm

    The time
    for the first part is
    t1 =2•s/5•v1,
    for the second part is
    t2 = 3•s/5•v2.
    The total time is
    t =t1+t2 =
    =(2•s/5•v1)+( 3•s/5•v2)=
    =(s/5) •(2/v1 + 3/v2) =
    =(s/5) •{(2•v2+3•v1)/(v1•v2)},
    v(ave) = distance/total time =
    =s/[(s/5) •{(2•v2+3•v1)/(v1•v2)}]=
    =5•(v1•v2)/(3•v1+2v2).

  • physics - , Friday, June 24, 2016 at 10:28am

    5v1v2/3v1+2*3/5

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