Posted by **Kate** on Friday, May 25, 2012 at 12:26am.

How do I put this parabola in standard form? Could someone show how they would put it in this form: (x - h)2 = 4p(y - k)

1. 4x^2+24x+128y-988=0

Please help! I'm lost.

## Answer This Question

## Related Questions

- math - 4x^2+24x+128y-988=0 in standard form
- Pecalculs - Can anyone put this parabola into this standard form: x-h = a(y-k)^2...
- Alg II/Trig - A parabola has a vertex at (0,0); a horizontal axis; and the point...
- Parabola - 3y^2+24y+72x-96=0 Can anyone put this in standard form: (y - k)2 = 4p...
- Precalc - How would I put this parabola in standard form: x^2-6x+8y-31 Here how ...
- Pre-Cal - I'm trying to put this parabola in standard form which is: (y-k)^2=4p(...
- Math - Write an equation in standard form for each parabola. Vertex (0, 0) and ...
- Algebra2 - A quadratic equation can be written in vertex form or in standard ...
- algebra 2 - A quadratic equation can be written in vertex form or in standard ...
- Algebra - I'm trying this again, I'd like the quadratic form, so i can then work...

More Related Questions