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February 1, 2015

February 1, 2015

Posted by **lindsay** on Thursday, May 24, 2012 at 11:27pm.

a. Find the length of AB

b. The gradient and equation of line AB

- geometry -
**HenrComp./yr * 5yrsy**, Friday, May 25, 2012 at 10:33pmGiven: A(1,1) B(3,4), C(3,1).

a. (AB)^2 = (3-1)^2 + (4-1)^2 = 13

AB = sqrt13.

b. m = (4-1) / (3-1) = 3/2.

Y = mx + b

1 = (3/2)*1 + b

b = 1-3/2 = -1/2.

Eq: Y = (3/2)x - 1/2.

- geometry -
**Henry**, Friday, May 25, 2012 at 10:36pmHenry

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