Posted by **j** on Thursday, May 24, 2012 at 10:52pm.

3. Determine that the vectors u=[t, 4, 2t+1] and v=[t+2, 1-t, -1] are perpendicular, find the possible values of the contant, t.

- Calculus -
**MathMate**, Friday, May 25, 2012 at 7:43am
Same as previous question,

http://www.jiskha.com/display.cgi?id=1337914331

Except that the dot-product equated to zero results in a quadratic equation.

So solve for possible values of t by solving the quadratic.

- Calculus -
**j**, Friday, May 25, 2012 at 12:14pm
t(t+2) + 4(1-t) - (2t+1) = 0

t = 1,3

like that?

- Calculus -
**MathMate**, Friday, May 25, 2012 at 1:26pm
Correct!

- Calculus -
**j**, Saturday, May 26, 2012 at 1:22am
thanks

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