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October 1, 2014

October 1, 2014

Posted by **j** on Thursday, May 24, 2012 at 10:52pm.

- Calculus -
**MathMate**, Friday, May 25, 2012 at 7:43amSame as previous question,

http://www.jiskha.com/display.cgi?id=1337914331

Except that the dot-product equated to zero results in a quadratic equation.

So solve for possible values of t by solving the quadratic.

- Calculus -
**j**, Friday, May 25, 2012 at 12:14pmt(t+2) + 4(1-t) - (2t+1) = 0

t = 1,3

like that?

- Calculus -
**MathMate**, Friday, May 25, 2012 at 1:26pmCorrect!

- Calculus -
**j**, Saturday, May 26, 2012 at 1:22amthanks

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