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Calculus

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3. Determine that the vectors u=[t, 4, 2t+1] and v=[t+2, 1-t, -1] are perpendicular, find the possible values of the contant, t.

  • Calculus - ,

    Same as previous question,
    http://www.jiskha.com/display.cgi?id=1337914331

    Except that the dot-product equated to zero results in a quadratic equation.

    So solve for possible values of t by solving the quadratic.

  • Calculus - ,

    t(t+2) + 4(1-t) - (2t+1) = 0
    t = 1,3

    like that?

  • Calculus - ,

    Correct!

  • Calculus - ,

    thanks

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