Posted by noel on Thursday, May 24, 2012 at 10:00pm.
y = 1/(x-2) + 3
y-3 = 1/(x-2)
x-2 = 1/(y-3)
x = 1/(y-3) + 2
so, f-1(x) = 1/(x-3) + 2
y = 2(x-4)^2 + 5
y-5 = 2(x-4)^2
(y-5)/2 = (x-4)^2
now, we can use ± root, so let's choose the + root:
√[(y-5)/2] = x-4
√[(y-5)/2]+4 = x
so, f-1(x) = √[(x-5)/2] + 4
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