A female whose mass is 130 kilograms is standing on a scale in an elevator that has an initial downward velocity of 6 meters per second and is accelerating upward at 7 meters per second. What's the magnitude of the apparent weight indicated by the scale?

force=weigh+mass*acceleration

= mass(g+a)

the initial velocity is without any meaning.

again-set up?

To find the magnitude of the apparent weight indicated by the scale, we need to consider the forces acting on the person in the elevator.

The apparent weight experienced by a person in an elevator depends on two main factors: the actual weight of the person and the acceleration of the elevator.

First, let's calculate the weight of the person. The weight can be found using the formula:

Weight = mass × gravitational acceleration

Given that the mass of the person is 130 kilograms, and the gravitational acceleration is approximately 9.8 meters per second squared, we can calculate the weight as follows:

Weight = 130 kg × 9.8 m/s^2 = 1274 N

Next, let's consider the acceleration of the elevator. In this case, the elevator is accelerating upward at 7 meters per second squared. However, we also need to account for the initial downward velocity of the elevator, which is 6 meters per second. Since the acceleration is in the opposite direction of the initial velocity, the net acceleration can be calculated by subtracting the initial downward velocity from the acceleration due to the upward acceleration.

Net Acceleration = Acceleration - Initial Velocity

Net Acceleration = 7 m/s^2 - (-6 m/s^2) = 13 m/s^2

Now, we can calculate the magnitude of the apparent weight using the following formula:

Apparent Weight = Weight + (mass × net acceleration)

Apparent Weight = 1274 N + (130 kg × 13 m/s^2)
Apparent Weight = 1274 N + 1690 N
Apparent Weight = 2964 N

Therefore, the magnitude of the apparent weight indicated by the scale is 2964 Newtons.