Posted by **Ethan** on Thursday, May 24, 2012 at 4:38pm.

An external force F is holding a bob of mass 725 g in a stationary position. The angle that the massless rope makes with the vertical is θ = 33°.

(a) What is the magnitude, F, of the force needed to maintain equilibrium in N?

(b) What is the tension in the rope in N?

- Physics -
**Elena**, Thursday, May 24, 2012 at 6:01pm
F =T•sinα ,

mg = T•cos α..

F/m•g = tan α,

F = m•g•tan α =0.725•9.8•0.65 =4.6 N,

T =F/sinα = 4.6/0.54 = 8.45 N.

- Physics -
**Ethan**, Thursday, May 24, 2012 at 8:28pm
I understand how the first and third equations are used to find the answers, but how is the second equation (mg = Tcosa) used?

- Physics -
**Elena**, Friday, May 25, 2012 at 1:06pm
The third equation is the result of division the first equation by the second equation

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